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w^2+6w-775=0
a = 1; b = 6; c = -775;
Δ = b2-4ac
Δ = 62-4·1·(-775)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-56}{2*1}=\frac{-62}{2} =-31 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+56}{2*1}=\frac{50}{2} =25 $
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